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SASInstitute Clinical Trials Programming Using SAS 9.4 Sample Questions:
1. Which two SDTM domains store information for the experimental design of the trial?
(Choose two.)
A) TV
B) TA
C) TD
D) TE
2. Given the following vital signs data: Baseline is defined as the last non-missing value prior to Day 1.
What is the value for the change from baseline for Week 1 for Subject 2?
A) -23
B) 11
C) 23
D) -11
3. A Statistical Analysis Plan (SAP) defines the selection process for baseline records. This instructs the programmer to choose the last non-missing analyte value prior to first study drug administration (date/time).
The DEMO data set contains the date/time of first study drug administration for subject:
What will be the resulting baseline values, as selected per the SAP instructions?
A) Option C
B) Option B
C) Option A
D) Option D
4. What is the primary purpose of programming validation?
A) Justify the means used to accomplish the outcome of a program and ensure its accurate representation of the original data.
B) Document all specifications pertaining to programmed output and ensure all were reviewed during the programming process.
C) Efficiently ensure any logic errors are discovered early in the programming process.
D) Ensure that the output from both the original program and the validation program match.
5. The first six (6) records from the LABS data set are shown below:
The following SAS program is written to reshape this data set and place it in a new data set named LBTR.
proc transpose data=labs out=lbtr(rename = (col1 = value));
by subjid sampldat;
var Calcium Glucose Hemoglobin;
run;
Which of the following DATA steps produces a data set that is equivalent to the LBTR data set created by the PROC TRANSPOSE step above?
A) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 _temporary_ ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
output;
end;
run;
B) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
end;
output;
run;
C) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
output;
end;
run;
D) data lbtr2(drop = i calcium glucose hemoglobin);
set labs;
array orig[3] calcium glucose hemoglobin;
array testcds[3] $ 10 _temporary_ ("CALCIUM" "GLUCOSE" "HEMOGLOBIN");
do i = 1 to 3;
value = orig[i];
_name_ = testcds[i];
end;
output;
run;
Solutions:
| Question # 1 Answer: B,D | Question # 2 Answer: D | Question # 3 Answer: D | Question # 4 Answer: A | Question # 5 Answer: A |
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